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# new peak power RPM formula

#### jaguar

##### Subscriber
Any math experts here? How do you simplify this equation to solve for RPM?
6.089/RPM + 1.98RPM = 14,918
It's part of my new formula for determining peak power RPM by transfer port duration and transfer/boost area. thanks in advance

- a d v e r t i s e m e n t -

#### jaguar

##### Subscriber
I figured it out.
I've analyzed numerous engines and found that using (time x area) / cc is a good formula for the exhaust port (when using blowdown area) but not for the transfers. I tried various formulas for the transfers and couldn't find one that worked on all engines. The only key I could find is that no transfers have less than a 1.43ms "transfer time" (see definition on my site). I offer a free Excel spreadsheet calculator on my site for people interested in correct modification of their engine.

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