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General Moto | Off-Topic Posts
flattrack technique
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[QUOTE="MikeT, post: 222676, member: 21398"] Correct Not really, the rock is moving outward in a big way. What Jaybird means (correct me if I'm wrong) when he says "plot it out, is to draw what's called a free body diagram of all the bodies in the experiment. When that diagram is plotted or drawn out, you can see all the forces acting on everything in the system. Lets take the rock and string example. In this example there are three pieces with many different forces, the rock, the string, and your hand. We, for simplicity because this is already getting too complicated, will eliminate the hand. The string (when spinning) has a forward vector (force) moving it around in a circle. It also has the force of its own mass pulling it, or pushing it outward (just as Jaybird pointed out, the car door is also pushing out) on the rock. The rock has the force of its own mass wanting it to continue in a straight line because of the centrepital force but it keeps going in a circle because of the string. As long as the maximum tensile force of the string is not exceeded by the centripetal force of the rock plus the mass of the string, then the whole system is in eqlibrium until your arm gets tired. Side note, in this example there is also the gravitational force acting on all involved, I didn't want to add more to the mix. Aren't we saying the same thing here? Can't we all just get along. Really, I think if you took my little story above and replaced the rock with your body on the flat track bike, the string with (more or less) traction (less because traction doesn't have any mass) and the spinning force also with traction, you'll have some good lap times! :D MikeT [/QUOTE]
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MX, SX & Off-Road Discussions
General Moto | Off-Topic Posts
flattrack technique
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