MikeT
~SPONSOR~
- Jan 17, 2001
- 4,095
- 11
Ok, I am having a little issue here trying to figure out some Physics and I haven't taken a Physics course in over twenty years. Don't be too hard on me about incorrect terminology as I'm sure I am wrong about a few things.
Here is the problem;
Backround: I have a garbage facility that has a concrete wall and they want to make the wall taller with some steel posts and basically make a raised fence connected to the top of the concrete wall.
Problem; I have calculated that when a 2857 Kilograms horizontal load is pushing on the new extension (no speed or impact), the bolts will be at their maximum capacity. The front end loaders will frequently throw a bucket full of garbage at the wall and I have calculated that 907Kg (bucket capacity) of garbage being thrown at 2.23 m/s (estimated speed) has the Kinetic energy of 2,255 joules. K=1/2 m*v^2.
What I am having trouble with in my mind is coming up with a way to determine how much the wall can take because I don't have the velocity component to stick in the equation. I do have the mass that it can resist, 2857Kg but no speed. I want to be able to say that the wall can resist xxxxxx Joules and it is more than the 2,255 joules being thrown at it.
Can anyone of you smart guys shed some light on this? If you need more information, I will be waiting with bated breath for any responses.
Thanks!!
Here is the problem;
Backround: I have a garbage facility that has a concrete wall and they want to make the wall taller with some steel posts and basically make a raised fence connected to the top of the concrete wall.
Problem; I have calculated that when a 2857 Kilograms horizontal load is pushing on the new extension (no speed or impact), the bolts will be at their maximum capacity. The front end loaders will frequently throw a bucket full of garbage at the wall and I have calculated that 907Kg (bucket capacity) of garbage being thrown at 2.23 m/s (estimated speed) has the Kinetic energy of 2,255 joules. K=1/2 m*v^2.
What I am having trouble with in my mind is coming up with a way to determine how much the wall can take because I don't have the velocity component to stick in the equation. I do have the mass that it can resist, 2857Kg but no speed. I want to be able to say that the wall can resist xxxxxx Joules and it is more than the 2,255 joules being thrown at it.
Can anyone of you smart guys shed some light on this? If you need more information, I will be waiting with bated breath for any responses.
Thanks!!
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