Sprocket Question

dmdee99

Member
Apr 24, 2006
123
0
It is about that time to get a new chain and sprocket and I got some questions.

I am currently running the following set up. 13 front and a 51 rear.

I am thinking about going back to the stock set up which is 13 front and 48 rear but I do not know what the effects will be. Can someone give me an explination on how the bike will handle with the 13 front and 48 rear. It has been so long since I ran the stock set up.

I do recall reading somewhere that if you add teeth to the stock set up you get more torq and if you do the opposite you get more top speed. Is this correct.

What happens if you add or subtract teeth to the front sprocket.

I mostly ride woods and trails. I do occasionally ride mx.

Thanks
 

nikki

Moto Junkie
Apr 21, 2000
5,802
1
dmdee99 said:
I do recall reading somewhere that if you add teeth to the stock set up you get more torq and if you do the opposite you get more top speed. Is this correct.

Yep, that's the basic deal. If you go bigger on the rear = more torque/quicker acceleration, if you go smaller = more top speed in each gear.

And general rule of thumb, the front sprocket has the opposite effect, and is similar to going 4 teeth in the back. But in general, you can think of it like a ratio.

For example:

53/13 = 4.1
48/12 = 4.0
52/13 = 4.0
51/13 = 3.9
47/12 = 3.9
50/13 = 3.8
53/14 = 3.8
52/14 = 3.7
48/13 = 3.7
50/14 = 3.6

So like a 48/12 and 52/13 are both a 4.0, so will have a pretty similar impact on the gearing. Another thing to keep in mind is the chain length, a bigger rear sprocket might need another link, and a with a smaller sprocket, you might need to cut off a link. Since you are getting a new chain you will be fine, but sometimes if you're switching with your current chain you might have issues.
 

russdaddy

Member
Jul 23, 2007
69
0
i have an RM 250 and i have a 13 tooth front and a 49 tooth rear and its pretty torquie but has a good top speed still
 

dmdee99

Member
Apr 24, 2006
123
0
Nikki,

Thanks for the kick a$$ response. That is the exact info I was looking for.

Thanks again.
 
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