WhiPit

Member
Mar 16, 2000
236
0
Guys-

I noticed on another thread that discusses shim stacks that the poster had shown two shims of equal diameter and thickness, with a side note that said basically "equals two".

EX: 11 x 0.10
11 x 0.10 (equals a two)

Sorry guys, but it does not! Dont get sucked into thinking that (for
example) that if you want a 0.20 shim in your stack and all you have
is two 10'sthat it's okay and that it's the same thing. It's not...
In fact, I recall finding out that in some instances it can take up to sixty (60!) 0.10 shims to equal one 0.20 shim.

Now, I don't know the math for this and everyone seems to have their own formula anyways. Maybe Jeremy has an answer we can all live with????
 

WhiPit

Member
Mar 16, 2000
236
0
dre - you are certianly correct and I apologize for my over sight!

Yes, generally sizes of that diameter - anything less than 12mm diameter - the "rule" does not apply. Those sizes are normally used as "bender shims". Meaning that other larger diameter shims bend over those diameters.

So let me rephrase: Example - if you needed 4 24x0.10 shims up against your piston, but only have 2 24x0.20, it isn't the same.

Got it? :D
 

Jeremy Wilkey

Owner, MX-Tech
Jan 28, 2000
1,453
0
Whipit,
I'm at my lap top and don't have the files on this computer. I'll attach to this post later. It's a very simple formula.
Regards,
Jer
 

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